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JavaScript

/*
Collect contiguous ranges. These are where the underlying is expected to be at the front-month.
Start with an empty array of calendars (the "position"). (The array will contain the final, optimized position.)
Starting at the leftmost strike that's within the user-defined spot-price range, find the cheapest (though not necessarily most capital-efficient) front-month/back-month combo, and append it to the calendar-array.
Check profitability, as follows:
Check profitability assuming the underlying expires at the leftmost spot-price of the leftmost range. The next spot-prices to check are at the strikes _within_ the range, followed by the rightmost spot-price of the range; followed by doing the same for the rest of the ranges.
If, at "expiration" (i.e. the front-month), the position is profitable at this spot-price [*1]:
If there are more spot-prices to check to the right of this one:
Check the next spot-price.
Else (i.e. if there are _not_ more spot-prices to check to the right of this one):
That means we're "covered". Return position.
Else (i.e. if, at expiration, the position is _not_ profitable at this spot-price):
Try to shift the rightmost calendar to the right (regardless of whether it's towards or away from the current spot-price) by one strike.
Check profitability starting from the leftmost spot-price-at-expiration, up to and including the spot-price we're currently evaluating:
If the tweaked position is profitable at this spot-price:
If we're holding by the spot-price we're currently evaluating:
Keep the tweaked position, and continue with it as we would with a "profitable-thus-far" position (i.e. [*1]).
Else (i.e. if we're _not yet_ holding by the spot-price we're currently evaluating):
Continue checking with the next spot-price.
Else (i.e. if the tweaked position is _not_ profitable at this spot-price):
If we're holding by the spot-price we're currently evaluating:
Shift, by one more strike, the rightmost calendar in the position.
Else if we're holding by the
*/
export const calculateBestCombinationOfCalendars(){
let cheapest = null;
front_months.forEach(front_month=>{
front_month.ranges.forEach(range=>{
range.back_months.forEach(back_month=>{
// begin by making a calendar at every available strike in the range.
})
})
})
}